In the given figure, AB || CD. If =50^ and =60^ , then =? - Vidyadip

Question

In the given figure, AB || CD. If $\angle\text{EAB}=50^\circ$ and $\angle\text{ECD}=60^\circ,$ then $\angle\text{AEB}=?$

✓

Answer

70º
Solution:
$\angle\text{BCD}=\angle\text{ABE}=60^\circ$ (Vertically opposite angle)
In $\triangle\text{EAB}$
$\angle\text{EAB}+\angle\text{EBA}+\angle\text{AEB}+180^\circ$ (Angle sum property)
$50^\circ+60^\circ+\angle\text{AEB}=180^\circ$
$\text{AEB}=70^\circ.$

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