MCQ
In the given figure, $AB \| CD$, If $\angle\text{ABO}=45^\circ$ and $\angle\text{COD}=100^\circ$ then $\angle\text{CDO}=?$
- A$45^\circ$
- ✓$35^\circ$
- C$25^\circ$
- D$30^\circ$
✓
Answer
Correct option: B.
$35^\circ$
$\angle\text{ABC}=\angle\text{BCD}=45^\circ$ (Alternate interior angles)
In $\triangle\text{COD}$
$\angle\text{COD}+\angle\text{CDO}+\angle\text{DCO}=180^\circ$ (Angle sum property)
$\angle\text{CDO}=180^\circ-100^\circ-45^\circ$
$\angle\text{CDO}=35^\circ.$
In $\triangle\text{COD}$
$\angle\text{COD}+\angle\text{CDO}+\angle\text{DCO}=180^\circ$ (Angle sum property)
$\angle\text{CDO}=180^\circ-100^\circ-45^\circ$
$\angle\text{CDO}=35^\circ.$
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