MCQ
In the given figure, $AB \| CD$. If $\text{BAO}=60^\circ$ and $\angle\text{OCD}=110^\circ,$ then $\angle\text{AOC}=?$ 
- A$40^\circ$
- ✓$50^\circ$
- C$60^\circ$
- D$70^\circ$
✓
Answer
Correct option: B.
$50^\circ$
Construction: Extend the line $CD$ such that it intersect $AO$ and is parallel to $AB$
$x = 60^\circ $ (Corresponding angles)
$x + y + 180^\circ - 110^\circ = 180^\circ $ (Angle sum property)
$y = 110^\circ - 60^\circ = 50^\circ .$
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