Question
In the given figure,
AB || DC prove that
$\triangle\text{DMU}\sim\triangle\text{BMV}$
AB || DC prove that
$\triangle\text{DMU}\sim\triangle\text{BMV}$
✓
Answer
Given, AB || DC 
In triangle DMU and BMV, we have $\angle\text{MUD}=\angle\text{MVB}$ Each angle is equal to 90° $\angle\text{UMD}=\angle\text{VMB}$ Each are vertically opposite angles. Therefore, by AA-criterion of similarity $\triangle\text{DMU}\sim\triangle\text{BMV}$
In triangle DMU and BMV, we have $\angle\text{MUD}=\angle\text{MVB}$ Each angle is equal to 90° $\angle\text{UMD}=\angle\text{VMB}$ Each are vertically opposite angles. Therefore, by AA-criterion of similarity $\triangle\text{DMU}\sim\triangle\text{BMV}$Need a full question paper?
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