In the given figure, ABCD and BDCE are parallelograms with common…

Download App

MCQ

In the given figure, $ABCD$ and $BDCE$ are parallelograms with common base $DC.$ If $BC ⊥ BD,$ then $\angle\text{BEC}=$

Image: https://vidyadip.s3.amazonaws.com/question/AsyCgyZgwqxVLWjV.png

✓
$60^\circ$
B
$30^\circ$
C
$150^\circ$
D
$120^\circ$

✓

Answer

Correct option: A.

$60^\circ$

$\angle\text{BCD}=30^\circ$
$\therefore\angle\text{BCD}=30^\circ$,
in $\triangle\text{CBD}$ by angle sum property of a triangle, we have
$\Rightarrow\angle\text{DBC}+\angle\text{BCD}+\angle\text{CDB}=180^\circ$
$\Rightarrow90^\circ+30^\circ+\angle\text{CDB}=180^\circ$
$\Rightarrow\angle\text{CDB}=180^\circ-120^\circ=60^\circ$
$\Rightarrow\angle\text{BEC}=60^\circ$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q. [1 Marks Each]" from Understanding Quadrilaterals→Understanding Quadrilaterals — all question types→MATHS STD 8 question papers→Gujarat Board STD 8 question papers→Gujarat Board question paper generator→

Understanding Quadrilaterals — MATHS STD 8 — Question

Answer

Need a full question paper?

Explore more

Similar questions