Question
In the given figure, ABCD is a ||gm in which AB = CD = 5cm and $\text{BD}\perp\text{DC}$ such that BD = 6.8cm. Then, the area of ABCD = ?
- 17cm2
- 25cm2
- 34cm2
- 68cm2
✓
Answer
- 34cm2
Solution:
Since ABCD is a ||gm, AB || CD.
ar(||gm ABCD) = base × height
= AB × BD
= 5 × 6.8
= 34cm2
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