MCQ
In the given figure, $\text{ABCD}$ is a $\| g m$ in which $\text{AB=CD}=5 \ cm$ and $BD \perp DC$ such that $BD=6.8 \ cm$. Then, the area of $\text{ABCD} =$ ?
- A$17 \ cm^2$
- B$25 \ cm^2$
- ✓$34 \ cm^2$
- D$68 \ cm^2$
✓
Answer
Correct option: C.
$34 \ cm^2$
Since $\text{ABCD}$ is a $\|g m, A B\| C D$.
$\operatorname{ar}(\| g m \text{ABCD} )=$ base $\times$ height
$=A B \times B D$
$=5 \times 6.8$
$=34 \ cm^2$
$\operatorname{ar}(\| g m \text{ABCD} )=$ base $\times$ height
$=A B \times B D$
$=5 \times 6.8$
$=34 \ cm^2$
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