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Areas of Parallelograms and Triangles — Maths STD 9 — Question

Maharashtra BoardEnglish MediumSTD 9MathsAreas of Parallelograms and Triangles1 Mark
MCQ
In the given figure, $\text{ABCD}$ is a ||gm in which $\text{DL}\perp\text{AB}.$ If $AB = 10\ cm$ and $DL = 4\ cm,$ then the $\ce{ar(\|gm ABCD)} = ?$
  • ✓
    $40 \ cm^2$
  • B
    $80 \ cm^2$
  • C
    $20 \ cm^2$
  • D
    $196 \ cm^2$
✓

Answer

Correct option: A.
$40 \ cm^2$
$\text{ABCD}$ is a $\| gm$ and $DL \perp AB$.
So, $D L$ is the height of the $\ce{\| gm ABCD}$.
$\ce{\operatorname{ar}(|\mid g m ABCD)}=$ base $\times$ height
$=A B \times D L$
$=10 \times 4$
$=40 cm^2$

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