Question
In the given figure ABCD is a square. Find the measure of $\angle\text{CAD}.$

Answer

In $\triangle\text{ADC},$
$\text{DA}=\text{DC}$
$\Rightarrow\angle\text{ACD}=\angle\text{DAC}=\text{x}^\circ$
Then, $\text{x}^\circ+\text{x}^\circ+90^\circ=180^\circ$
$\Rightarrow2\text{x}^\circ=180^\circ-90^\circ$
$\Rightarrow2\text{x}^\circ=90^\circ$
$\Rightarrow\text{x}^\circ=45^\circ$

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