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Constructions — Maths STD 7 — Question

Maharashtra BoardEnglish MediumSTD 7MathsConstructions3 Marks
Question
In the given figure, AOB is a straight line and OC is ray such that $\angle\text{AOC}=(3\text{x}+20)^\circ$ and $\angle\text{BOC}=(2\text{x}-10)^\circ.$ Find the value of x and hence find (i) $\angle\text{AOC}$ and $\angle\text{BOC.}$
✓

Answer

Here, $3\text{x}+20+2\text{x}-10=180$
$\Rightarrow5\text{x}+10=180$
$\Rightarrow5\text{x}=170$
$\Rightarrow\text{x}=34$
$\angle\text{AOC}=(3\times34+20)^\circ$
$=(102+20)^\circ$
$=122^\circ$
$\angle\text{BOC}=(2\times34-10)^\circ$
$=(68-10)^\circ$
$=58^\circ$

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