MCQ
In the given figure, $AOB$ is a straight line. If $\angle\text{AOC}=(3\text{x}+10)^\circ$ and $\angle\text{BOC}=(4\text{x}−26)^\circ.$ then $\angle\text{BOC}=?$
- A$76^\circ$
- B$106^\circ$
- C$96^\circ$
- ✓$86^\circ$
✓
Answer
Correct option: D.
$86^\circ$
We have,
$\angle\text{AOC}+\angle\text{BOC}=180^\circ$ [Since $AOB$ is a straight line]
$\Rightarrow 3x + 10 + 4x - 26 = 180^\circ$
$\Rightarrow 7x = 196^\circ$
$\Rightarrow x = 28^\circ$
$\therefore\angle\text{BOC}=[4\times28−26]^\circ$
Hence, $\angle\text{BOC}=86^\circ.$
$\angle\text{AOC}+\angle\text{BOC}=180^\circ$ [Since $AOB$ is a straight line]
$\Rightarrow 3x + 10 + 4x - 26 = 180^\circ$
$\Rightarrow 7x = 196^\circ$
$\Rightarrow x = 28^\circ$
$\therefore\angle\text{BOC}=[4\times28−26]^\circ$
Hence, $\angle\text{BOC}=86^\circ.$
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