Question
In the given figure, $\frac{ EA }{ EC }=\frac{ EB }{ ED }$, prove that $\triangle EAB \sim \triangle ECD$
✓
Answer
In $\triangle EAB$ and $\triangle ECD$
$\frac{EA}{EC}=\frac{EB}{ED}$
$\angle AEB=\angle CED$
$\triangle EAB \sim \triangle ECD$
$\frac{EA}{EC}=\frac{EB}{ED}$
$\angle AEB=\angle CED$
$\triangle EAB \sim \triangle ECD$
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