Question
In the given figure, find $\angle P Q R$.
✓
Answer
SQR is a straight line
∴ ∠SQT + ∠TQP + ∠PQR = 180°
⇒ x + 70° + 20° – x + ∠PQR = 180°
⇒ 90° + ∠PQR = 180°
⇒ ∠PQR = 180°− 90° = 90°
Hence ∠PQR = 90°
∴ ∠SQT + ∠TQP + ∠PQR = 180°
⇒ x + 70° + 20° – x + ∠PQR = 180°
⇒ 90° + ∠PQR = 180°
⇒ ∠PQR = 180°− 90° = 90°
Hence ∠PQR = 90°
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The mean of a certain number of observations is 32. Find the resulting mean, if the observation is decreased by 20%.
A coin is tossed 80 times and the head is obtained 38 times. Now, if a coin tossed once, what will the probability of getting a head
Multiply: $(2x - 3y)(2x + 3y)$
→Evaluate: -8 – {- 6 (9 – 11) + 18 ÷ -3}
Express as a ratio : $0.36 \%$
→Find the unknown marked angles in the given figure:
Find die value of: 6.25 of 8.4 – 4.7 of 3.24
If $x$ is $20 \%$ less than $y$, find: $\frac{x}{y-x}$
→Convert given fraction into a fraction with equal denominator:
$\frac{5}{6} \text { and } \frac{7}{9}$
→$\frac{5}{6} \text { and } \frac{7}{9}$
Divide: 7.644 by 1.4