MCQ
- A40º
- B100º
- C50º
- D90º
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Similar questions
Each of two equal sides of an isoscale right triangle is 10cm long. Its area is:
The signs of abscissa and ordinate of a point in quadrant III are:
The number of dimensions, a point has
(207 × 193) = ?
- 39851
- 39951
- 39961
- 38951
When p(x) = 4x3 - 12x2 + 11x - 5 is divided by (2x - 1), the remainder is:
- 0
- -5
- -2
- 2
If $\bar{\text{x}_1},\bar{\text{x}}_2,\ _{\dots},\bar{\text{x}}_\text{n}$ are the means of n group with n1, n2, ..., nn number of observation respectively then the mean $\bar{\text{x}}$ of all the groups taken together is:
→- $\sum\limits_{\text{i}=1}^\text{n}\text{n}_\text{i}\bar{\text{x}}_\text{i}$
- $\frac{\sum\limits_{\text{i}=1}^\text{n}\text{n}_\text{i}\bar{\text{x}}_\text{i}}{\text{n}^2}$
- $\frac{\sum\limits_{\text{i}=1}^\text{n}\text{n}_\text{i}\bar{\text{x}}_\text{i}}{\sum\limits_{\text{i}=1}^\text{n}\text{n}_\text{i}}$
- $\frac{\sum\limits_{\text{i}=1}^\text{n}\text{n}_\text{i}\bar{\text{x}}_\text{i}}{2\text{n}}$
Write the correct answer in the following:
In Fig. if AOB is a diameter of the circle and AC = BC, then $\angle\text{CAB}$ is equal to:
→In Fig. if AOB is a diameter of the circle and AC = BC, then $\angle\text{CAB}$ is equal to:
- 30°.
- 60°.
- 90°.
- 45°.
The quadrilateral formed by joining the midpoints of the sides of a quadrilateral ABCD, taken in order, is a rectangle, if:
- ABCD is a Parallelogram
- ABCD is rectangle
- Diagonals of ABCD are equal
- Diagonals of ABCD are perpendicular to each other.
If area of a || gm with sides a and b is A and that of a rectangle with sides a and b is B, then:
The equation of a line parallel to y-axis and 7 units to the left of origin is: