MCQ
In the given figure, if $\angle\text{CAB}=50^\circ$ and $\angle\text{ABC}=70^\circ,$ then $\angle\text{ADB}$ is equal to: 

- ✓$60^\circ$
- B$80^\circ$
- C$70^\circ$
- D$50^\circ$

In triangle $ABC, \angle\text{A}+\angle\text{B}+\angle\text{C}=180^\circ$
$\Rightarrow\angle\text{C}=60^\circ$
$\angle\text{ACB}=\angle\text{ADB}=60^\circ ($Angle made by the same chord are equal$)$
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