Question
In the given figure potential difference between $A$ and $B$ is :-............. $V$



$\therefore$ equivalent resistance of circuit
$=\left(10+\frac{10 \times 10}{10+10}\right) \mathrm{k} \Omega=15 \mathrm{k} \Omega$
$\therefore$ current through cell $ = \frac{{30}}{{15}}\frac{V}{{{\rm{k}}\Omega }} = 2\,{\rm{mA}}$
$\therefore$ current between $\mathrm{A}$ and $\mathrm{B}=1 \mathrm{\,mA}$
$\therefore V_{A B}=10 \mathrm{\,k} \Omega \times 1 \mathrm{\,mA}=10 \mathrm{\,V}$
$\therefore(3)$
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$B=\frac{4}{\pi} \times 10^{-3}\, {T}\left(1-\frac{{t}}{100}\right)$
The energy dissipated by the coil before the magnetic field is switched off completely is $E=.....\,{m} J.$
