Question
In the given figure potential difference between $A$ and $B$ is :-............. $V$

Answer

c
Since diode in forward bias so it behaves as short circuit.

$\therefore$ equivalent resistance of circuit

$=\left(10+\frac{10 \times 10}{10+10}\right) \mathrm{k} \Omega=15 \mathrm{k} \Omega$

$\therefore$ current through cell $ = \frac{{30}}{{15}}\frac{V}{{{\rm{k}}\Omega }} = 2\,{\rm{mA}}$

$\therefore$ current between $\mathrm{A}$ and $\mathrm{B}=1 \mathrm{\,mA}$

$\therefore V_{A B}=10 \mathrm{\,k} \Omega \times 1 \mathrm{\,mA}=10 \mathrm{\,V}$

$\therefore(3)$

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