Question
In the given figure, $\text{AB}||\text{CD},\angle\text{ABO}=60^\circ$ and $\angle\text{CDO}=40^\circ.$ Then, find $\angle\text{BOD}.$

Answer


$\angle\text{ABO}=60^\circ$
$\angle\text{CDO}=40^\circ$
$\angle\text{ABO}=\angle\text{BOC}=60^\circ$ [alternate angles]
$\angle\text{CDO}=\angle\text{DOC}=40^\circ$ [alternate angles]
$\angle\text{BOD}=\angle\text{BOC}+\angle\text{DOC}$
$=60^\circ+40^\circ=100^\circ$

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