Question
In the given figure, $\text{CE}||\text{BA}.$ If $\angle\text{BAC}=70^\circ$ and $\angle\text{ECD}=50^\circ,$ find $\angle\text{ACB}.$ 
✓
Answer
Here $\text{AB}||\text{EC}$
$\therefore\angle\text{BAC}=\angle\text{ACE}=70^\circ$ (alternate angles)
$\angle\text{BCA}+\angle\text{ACE}+\angle\text{ECD}=180^\circ$
$\angle\text{BCA}=180^\circ-120^\circ$
$\angle\text{BCA}=60^\circ$
$\therefore\angle\text{BAC}=\angle\text{ACE}=70^\circ$ (alternate angles)
$\angle\text{BCA}+\angle\text{ACE}+\angle\text{ECD}=180^\circ$
$\angle\text{BCA}=180^\circ-120^\circ$
$\angle\text{BCA}=60^\circ$
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