MCQ
In the given figure, $\text{EAD}\perp\text{BCD}.$ Ray $\text{FAC}$ cuts ray $\text{EAD}$ at a point $A$ such that $\angle\text{EAF}=30^\circ.$ Also, in $\triangle\text{BAC},\angle\text{BAC}=\text{x}^\circ$ and $\angle\text{ABC}=(\text{x}+10).$ Then, value of $x$ is:
- A$20^\circ$
- ✓$25^\circ$
- C$30^\circ$
- D$35^\circ$