MCQ
In the given figure, the shaded area is
Image
  • A
    $50(\pi-2) cm ^2$
  • $16(\pi-2) cm ^2$
  • C
    $16(\pi+2) cm ^2$
  • D
    $5(\pi-2) cm ^2$

Answer

Correct option: B.
$16(\pi-2) cm ^2$
We have, radius $=8 \ cm$ and $\theta=90^{\circ}$
$\therefore \quad$ Area of minor segment $=$ Area of sector $-$ Area of $\triangle \text{A O B}$
$=\frac{\theta}{360^{\circ}} \times \pi r^2-\frac{1}{2} \times$ base $\times$ height 
$=\frac{90^{\circ}}{360^{\circ}} \times \pi \times(8)^2-\frac{1}{2} \times 8 \times 8$
$=\frac{64}{4} \pi-32=16(\pi-2) \ cm ^2$

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