MCQ
In the given figure, the value of $y$ is:


- A$30^\circ $
- B$15^\circ$
- ✓$20^\circ$
- D$22.5^\circ$

Since, sum of all the angles on a straight line is $180^\circ .$
Therefore, $6\text{y}+\text{y}+2\text{y}=180^\circ$
$\Rightarrow9\text{y}=180^\circ$
$\Rightarrow\frac{180^\circ}{9}$
$\therefore\text{y}=20^\circ$
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