In the given potentiometer circuit length of the wire $AB$ is $3\, m$ and resistance is $R = 4.5 \, \Omega$ . The length $AC$ for no deflection in galvanometer is
A$2\, m$
B$1.8\, m$
Cdependent on $r_1$
D
none of these
Medium
Download our app for free and get started
D
none of these
d since cell connected in secondary circuit is in wrong way so we will not get balancing point.
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
$10\, Cells$, each of $emf$ $'E'$ and internal resistance $'r'$, are connected in series to a variable external resistance. Figure shows the variation of terminal potential difference of their combination with the current drawn from the combination.$Emf$ of each cell is ................ $V$
In the circuit shown in figure, potential difference between points $A$ and $B$ is $16\, V$. The current passing through $2\,\Omega $ resistance will be ................. $\mathrm{A}$
The given figure represents an arrangement of potentiometer for the calculation of internal resistance $(r)$ of the unknown battery $(E)$. The balance length is $70.0\, cm$ with the key opened and $60.0\,cm$ with the key closed. $R$ is $132.40 \Omega $. The internal resistance $(r)$ of the unknown cell will be.......$\Omega$ (Given $E_o > E$) :-
A cylindrical resistance is connected across battery $\varepsilon $ . Cylinder has uniform free electron density, mid part of cylinder has larger radius as shown in figure. Then $V_d$ (drift velocity) $V/S$ (distance across the length of the resistance)
A primary cell has an $e.m.f.$ of $1.5\,volts$, when short-circuited it gives a current of $3$ amperes. The internal resistance of the cell is .............. $ohm$
A uniform metallic wire has a resistance of $18\,\Omega $ and is bent into an equilateral triangle. Then, the resistance between any two vertices of the triangle is .................. $\Omega$