MCQ
In the given reaction :

$\begin{array}{*{20}{c}}
  O \\ 
  {||} \\ 
  {{C_6}{H_5} - C - C{H_3}} 
\end{array}\mathop {\xrightarrow{{(i)\,B{r_2}/KOH}}}\limits_{(ii)\,{H^ \oplus }} CHB{r_3} + [X]$

$[X]$ will be :

  • A
    $C_6H_5-CHO$
  • $C_6H_5COOH$
  • C
    $C_6H_5-CH_2OH$
  • D
    $CH_3COOH$

Answer

Correct option: B.
$C_6H_5COOH$
b

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