$\begin{array}{*{20}{c}}
O \\
{||} \\
{C{H_3} - C - C{H_3}}
\end{array}\mathop {\xrightarrow{{Conc.{H_2}S{O_4}}}}\limits_{Distillation} [X]$
$[X]$ will be :
- AMethyl oxide
- BPhorone
- ✓$1, 3, 5-$ Trimethylbenzene
- D$2-$ Butyne
$\begin{array}{*{20}{c}}
O \\
{||} \\
{C{H_3} - C - C{H_3}}
\end{array}\mathop {\xrightarrow{{Conc.{H_2}S{O_4}}}}\limits_{Distillation} [X]$
$[X]$ will be :
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$\mathrm{Sn}(\mathrm{s})\left|\mathrm{Sn}^{2+}(\mathrm{aq}, 1 \mathrm{M}) \| \mathrm{Pb}^{2+}(\mathrm{aq}, 1 \mathrm{M})\right| \mathrm{Pb}(\mathrm{s})$
the ratio $\frac{\left[\mathrm{Sn}^{2+}\right]}{\left[\mathrm{Pb}^{2+}\right]}$ when this cell attains equilibrium is
(Given $\mathrm{E}_{\mathrm{Sn}^{2+} / \mathrm{Sn}}^{0}=-0.14 \mathrm{\;V}$ $\left.\mathrm{E}_{\mathrm{Pb}^{+2}/{\mathrm{Pb}}}^{0}=-0.13 \;\mathrm{V}, \frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.06\right)$
$(\log \,4 = 0.60,\, \log \,5 = 0.69)$