MCQ
In the given reaction :
$CH_3-CH_2-COOH$ $\mathop {\xrightarrow{{(i)\,AgN{O_3}}}}\limits_{(ii)\,B{r_2}/\Delta } $ $[X]$
$[X]$ will be :
- ✓Ethyl bromide
- BPropyl bromide
- CPropyl propanoate
- DAll of these
$CH_3-CH_2-COOH$ $\mathop {\xrightarrow{{(i)\,AgN{O_3}}}}\limits_{(ii)\,B{r_2}/\Delta } $ $[X]$
$[X]$ will be :
The treatment with bromine results in replacement of alpha hydrogen atom with bromine.
Heating results in decarboxylation.
Hence, the end product is ethyl bromide (compound $X$).
$CH _3- CH _2- COOH \underset{( ii ) Br _2 / \Delta i / ANO }{\longrightarrow} CH _3-\underset{[ X ]}{ CH _2}- Br$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| List $I$ Vitamin | List $II$ Deficiency disease |
| $A$ Vitamin $A$ | $I.$ Beri-Beri |
| $B$ Thiamine | $II.$ Cheilosis |
| $C$ Ascorbic acid | $III.$ Xeropthalmia |
| $D$ Riboflavin | $IV.$ Scurvy |
Choose the correct answer from the options given below: