In the given reaction $\begin{array}{*{20}{c}}
{{C_6}{H_5} - C - C{H_3}} \\
{||} \\
O
\end{array}$ $\xrightarrow{{N{H_2}OH/{H^ \oplus }}}X\xrightarrow{{Na/{C_2}{H_5}OH}}Y$. $Y$will be

Question

A$\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - N{H_2}} \\
{|\,\,\,\,} \\
{\,C{H_3}}
\end{array}$
B$\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - NH - C{H_3}} \\
{\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
C$\begin{array}{*{20}{c}}
{{C_6}{H_5} - C - NH - C{H_3}} \\
{\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,O\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
D$\begin{array}{*{20}{c}}
{C{H_3} - C - NH - {C_6}{H_5}} \\
{\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$

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