MCQ
In the given reaction sequence :

$CH_3-CH_2-OH$ $\mathop {\xrightarrow{{(i)\,KMn{O_4}/\mathop O\limits^\Theta  H/\Delta }}}\limits_{(ii)\,{H^ \oplus }} (A)\mathop {\xrightarrow{{(i)\,SOC{l_2}}}}\limits_{(ii)\,N{H_3}/\Delta } (B)$ $\xrightarrow{{B{r_2}/KOH}}(C)$

$(C)$ will be :

  • Methylamine
  • B
    Eltylamine
  • C
    Propylamine
  • D
    Acetamide

Answer

Correct option: A.
Methylamine
a
Ethanol is oxidized with potassium permanganate in alkaline medium followed by acidification to obtain acetic acid (compound $A$). The carboxylic group is converted to acid chloride by thionyl chloride. This followed by reaction with ammonia to form acetamide. Hoffmann bromide degradation gives methylamine (compound $C$).

$CH _3- CH _2- OH \underset{\text { (ii) } H ^{\oplus}}{\stackrel{\text { (i) } KMnO _4 / O ^{\ominus} H / \Delta}{\longrightarrow}} CH _3-\underset{\text { (A) }}{ COOH } \underset{\text { (ii) } NH _3 / \Delta}{\stackrel{\text { (i) } SOCl _2}{\longrightarrow}} CH _3-CONH _2 \stackrel{ Br _2 / KOH }{\longrightarrow} CH _3 NH _2$

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