MCQ
In the hydrocarbon,
$\mathop C\limits_6 {H_3} - \mathop C\limits_5 H = \mathop C\limits_4 H - \mathop C\limits_3 {H_2} - \mathop C\limits_2 \equiv \mathop C\limits_1 H$
The state of hybridization of carbons $1, 3$ and $5$ are in the following sequence
- A$sp, sp^2, sp^3$
- B$sp^3, sp^2, sp$
- C$sp^2, sp, sp^3$
- ✓$sp, sp^3, sp^2$
