- ✓$37.33$
- B$45.33$
- C$35.33$
- D$43.33$
$10\, \mathrm{m} \,\mathrm{mol} \,\mathrm{H}_{2} \mathrm{SO}_{4}=20\, \mathrm{m}\, \mathrm{mol}$ of $\mathrm{NH}_{3}$
$\left[\mathrm{H}_{2} \mathrm{SO}_{4}+2 \mathrm{NH}_{3} \longrightarrow\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}\right]$
$1\, \mathrm{mol}\; \mathrm{NH}_{3}$ contains $14 \,\mathrm{g}$ nitrogen $20 \times 10^{-3}\, \mathrm{mol}\; \mathrm{NH}_{3}$ contains $14 \times 20 \times 10^{-3}$ nitrogen
$0.75\, \mathrm{g}$ of sample contains
$\%$ Nitrogen $=\frac{14 \times 20 \times 10^{-3}}{0.75} \times 100=37.33 \%$
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$CH_3-CH=O + C_6H_5-CH=O$ $\xrightarrow[\Delta ]{{\mathop O\limits^\Theta H(aq)}}$ $\mathop X\limits_{({C_4}{H_6}O)} $ $+$ $\mathop Y\limits_{({C_9}{H_8}O)} $
In the light of the above statements, choose the correct answer from the options given below :