MCQ
In the modern periodic table, the place of the element with atomic number $31$ is in
- A$s$ - block
- B$d$- block
- ✓$p$ -block
- D$f $-block
✓
Answer
Correct option: C.
$p$ -block
c
$(c) p$-block; $_{31}Ga \to \left[ {Ar} \right]3{d^{10}}4{s^2}{p^1}$.
$(c) p$-block; $_{31}Ga \to \left[ {Ar} \right]3{d^{10}}4{s^2}{p^1}$.
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