MCQ
In the nuclear reaction: $X(n,\,\alpha ){\,_3}L{i^7}$ the term $X$ will be
- ✓$_5{B^{10}}$
- B$_5{B^9}$
- C$_5{B^{11}}$
- D$_2H{e^4}$
✓
Answer
Correct option: A.
$_5{B^{10}}$
a
(a) $X(n,\;\alpha )\;_3^7Li{ \Rightarrow _Z}{X^A}{ + _0}{n^1} \to 3L{i^7}{ + _2}H{e^4}$
(a) $X(n,\;\alpha )\;_3^7Li{ \Rightarrow _Z}{X^A}{ + _0}{n^1} \to 3L{i^7}{ + _2}H{e^4}$
$Z = 3 + 2 = 5$ and $A= 7+4 -1 =10$
${\therefore _5}{X^{10}}{ = _5}{B^{10}}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Two cells of $emfs$ $E_1$ and $E_2$ and internal resistances $r_1$ and $r_2$ are connected in parallel. The $emf$ and internal resistance of the equivalent source is
→A clock $S$ is based on oscillations of a spring and a clock $P$ is based on pendulum motion. Both clocks run at the same rate on earth. On a planet having same density as earth but twice the radius then
→Needles $N_I, N_2$ and $N_3$ are made of a ferromagnetic, a paramagnetic and a diamagnetic substance respectively. A magnet when brought close to them will
→The efficiency of a Carnot engine depends upon
The graph of displacement v/s time is given below Its corresponding velocity-time graph will be
A condenser of $2\,\mu F$ capacitance is charged steadily from $0$ to $5\,C$. Which of the following graph represents correctly the variation of potential difference $(V)$ across it's plates with respect to the charge $(Q)$ on the condenser?
→If $r$ denotes the distance between the sun and the earth, then the angular momentum of the earth around the sun is proportional to
→In an $AC$ generator, a coil with $N$ turns, all of the same area $A$ and total resistance $R$, rotates with frequency $\omega $ in a magnetic field $B$. The maximum value of $emf$ generated in the coil is
→A man standing on the roof of a house of height $h$ throws one particle vertically downwards and another particle horizontally with the same velocity $u$. The ratio of their velocities when they reach the earth's surface will be
→Assertion : The ferromagnetic substance do not obey Curie’s law.
Reason : At Curie point a ferromagnetic substance start behaving as a paramagnetic substance.