Question
In the periodic table, the element with atomic number $16$ will be placed in the group
✓
Answer
d
$(d)$ $16$-$1{s^2}2{s^2}2{p^6}3{s^2}3{p^4}$ there are $6{e^ - }$ in outer most shell therefore its group is $VI^{th}A.$
$(d)$ $16$-$1{s^2}2{s^2}2{p^6}3{s^2}3{p^4}$ there are $6{e^ - }$ in outer most shell therefore its group is $VI^{th}A.$
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