MCQ
In the reaction $2{H_2}O \rightleftharpoons {H_3}{O^ + } + O{H^ - }$, water is
- AA weak base
- BA weak acid
- ✓Both a weak acid and a weak base
- DNeither an acid nor a base
✓
Answer
Correct option: C.
Both a weak acid and a weak base
(c)Because their conjugate base and conjugate acids are strong.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which of the following is $E$ isomer :
→Given below are two statements: one is labelled as Assertion $(A)$ and the other is labelled as Reason $(R)$
→Assertion $(A) :$ At $10^{\circ} C$, the density of a $5\, M$ solution of $KCl$ [atomic masses of $K$ and $Cl$ are $39$ and $35.5\, g \,mol ^{-1}$ ]. The solution is cooled to $-21^{\circ} C$. The molality of the solution will remain unchanged.
Reason $(R):$ The molality of a solution does not change with temperature as mass remains unaffected with temperature.
In the light of the above statements, choose the correct answer from the options given below
The $IUPAC$ name of the compound is _________.
→$10\,N$ and $\frac{1}{{10}}\,N$ solution is called
→The correct increasing order for bond angles among $BF _3, PF _3$ and $C \ell F _3$ is :
→Specific conductance of $0.2\, M$ electrolyte solution at $20\,^oC$ temperature is $2.48\times10^{-4}\, ohm^{-1}\, cm^{-1}$ then the molar conductance of solution will be ............ $\mathrm{ohm}^{-1} \mathrm{cm}^{2} \mathrm{mol}^{-1}$
→Which of the following compound does not give positive Fehling's test
$\alpha -D(+)$ glucose and $\alpha -D(+)$ glucose are
→$(i)$ Diastereomers $(ii)$ Geometrical isomers
$(iii)$ Epimers $(iv)$ Anomers
$(v)$ Enantiomers
The spin only magnetic moment value of the ion among $\mathrm{Ti}^{2+}, \mathrm{V}^{2+}, \mathrm{Co}^{3+}$ and $\mathrm{Cr}^{2+}$, that acts as strong oxidising agent in aqueous solution is .......... BM (Near integer).
→(Given atomic numbers: $\mathrm{Ti}: 22, \mathrm{~V}: 23, \mathrm{Cr}: 24$, Co: $27$)
In the reaction sequence :
→$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,||} \\
{C{H_3} - C - H}
\end{array}$ $\mathop {\xrightarrow{{HCN}}}\limits_{\mathop O\limits^\Theta H} (A)\mathop {\xrightarrow{{{H_2}O/{H^ \oplus }}}}\limits_\Delta $ Product
Product will be :