MCQ
In the reaction, ${H_2}C = C{H_2}\xrightarrow{\begin{subarray}{l}
{\text{cold alkaline}} \\
{\text{KMn}}{{\text{O}}_{\text{4}}}
\end{subarray} }(A)$ Product $A$ is :
{\text{cold alkaline}} \\
{\text{KMn}}{{\text{O}}_{\text{4}}}
\end{subarray} }(A)$ Product $A$ is :
- ✓Ethylene glycol
- BAcetic acid
- CEthane
- DButyric acid
