MCQ
In the reaction :$I_2 + 2S_2O_3^{2-} \to 2I^- + S_4O_6^{2-}$
  • A
    $I_2$ is reducing agent.
  • $I_2$ is oxidising agent and $S_2O_3^{2-}$ is reducing agent.
  • C
    $S_2O_3^{2-}$ is oxidising agent.
  • D
    $I_2$ is reducing agent and $S_2O_3^{2-}$ is oxidising agent.

Answer

Correct option: B.
$I_2$ is oxidising agent and $S_2O_3^{2-}$ is reducing agent.
b
$\stackrel{0}{I}_2 \rightarrow \stackrel{0^{-}}{2I}$

$I _2$ undergoes reduction hence acts as oxidising agents.

$S _2^{+2} O _6^{2-} \rightarrow S _4^{+2.5} O _6^{2-}$

It undergoes oxidation hence acts as a reducing agent.

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