MCQ
In the reaction sequence $CH _{2}= CH _{2}$ $\xrightarrow[{{\text{acid}}}]{{{\text{Hypochlorgys}}}}X\xrightarrow{Y}$ $\begin{array}{*{20}{c}}
  {C{H_2}OH} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_2}OH} 
\end{array}$

$X$ and $Y$ respectively are:

 

  • A
    see figure and heat
  • B
    $CH _{3} CH _{2} Cl$ and $NaOH$
  • C
    $CH _{3} CH _{2} OH$ and $H _{2} SO _{4}$
  • $CH _{2} ClCH _{2} OH$ and $NaHCO _{3}$

Answer

Correct option: D.
$CH _{2} ClCH _{2} OH$ and $NaHCO _{3}$
d
The chemical reaction is shown below:

$H _{2} C = CH _{2}$ $\xrightarrow{{HOCl}}$ $\mathop {\begin{array}{*{20}{c}}
  {OH\,\,\,Cl} \\ 
  {|\,\,\,\,\,\,\,\,|} \\ 
  {{H_2}C - C{H_2}} 
\end{array}}\limits_{(X)} $$\xrightarrow{{NaHC{O_3}}}$$\mathop {\begin{array}{*{20}{c}}
  {C{H_2}OH} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_2}OH} 
\end{array}}\limits_{(Y)} $

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