MCQ
In the reaction, $\ \ \ \ \ \ \ \ \ \ \ \ \ \text{Br}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\text{CH}_3-\text{CH}_2\xrightarrow[\Delta]{\text{alc. KOH}}\text{A,} A$ is :
  • $ \mathrm{CH}_2=\mathrm{CH}_2 $
  • B
    $ \mathrm{CH}_3 \mathrm{CH}_3 $
  • C
    $\text{CH}\equiv\text{CH}$
  • D
    Both $(a)$ and $(b)$

Answer

Correct option: A.
$ \mathrm{CH}_2=\mathrm{CH}_2 $

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