Question
In $\triangle A B C, \angle B=60^{\circ}, \angle C=40^{\circ}, A L \perp B C$ and $A D$ bisects $\angle A$ such that $L$ and $D$ lie on side $B C$. Find $\angle L A D$.
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x:
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$5$ |
$6$
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$7$
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$8$
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$9$
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y:
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$4$
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$8$
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$14$
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$11$
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$3$
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