MCQ
In $\triangle A B C, \angle B=\angle C$ and ray $A X$ bisects the exterior angle $\angle D A C$. If $\angle D A X=70^{\circ}$, then $\angle A C B=$
- A$35^{\circ}$
- B$90^{\circ}$
- ✓$70^{\circ}$
- D$55^{\circ}$
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