MCQ
In triangles $ABC$ and $DEF, AB = FD$ and $\angle\text{A} = \angle\text{D}.$ The two triangles will be congruent by $SAS$ axiom if:
- A$AC = EF$
- B$BC = EF$
- ✓$AC = DE$
- D$BC = DE$
✓
Answer
Correct option: C.
$AC = DE$
Given: $\triangle\text{ABC}$ and $\triangle\text{DEF}, \ \text{AB = FD}$ and $\angle\text{A} = \angle\text{D}$
The two triangles will be congruent by $SAS$ axiom if two sides including one angle of one triangle is equal to the another triangle.
Hence, $AC = DE$ (As $\angle\text{A}$ is between $AB$ and $AC)$
The two triangles will be congruent by $SAS$ axiom if two sides including one angle of one triangle is equal to the another triangle.
Hence, $AC = DE$ (As $\angle\text{A}$ is between $AB$ and $AC)$
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