MCQ
In $\triangle\text{ABC}$ and $\triangle\text{DEF,}$ it is given that $AB = DE$ and $BC = EF$. In order that $\triangle\text{ABC}\cong\triangle\text{DEF},$ we must have:
  • A
    $\angle\text{A}=\angle\text{D}$
  • $\angle\text{B}=\angle\text{E}$
  • C
    $\angle\text{C}=\angle\text{F}$
  • D
    none of these

Answer

Correct option: B.
$\angle\text{B}=\angle\text{E}$
In $\triangle\text{ABC}$ and $\triangle\text{DEF},$
$AB = DE$ and $BC = EF$
SO, the induded angles should be equal for the triangle to be congurent by the $SAS$ congruence criterion.
Thus, we must have $\angle\text{B}=\angle\text{E}.$

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