MCQ
In $\triangle\text{ABC}$ and $\triangle\text{DEF}$ its is given that $\angle\text{B}=\angle\text{E}$ and $\angle\text{C}=\angle\text{F}$ in order that $\triangle\text{ABC}≅\triangle\text{DEF}$ we must have,
  • A
    $AC = DE$
  • $BC = EF$
  • C
    $AB = DF$
  • D
    $\angle\text{A}=\angle\text{D}$

Answer

Correct option: B.
$BC = EF$
In $\triangle\text{ABC}$ and $\triangle\text{DEF}$
$\angle\text{B}=\angle\text{E}$ and $\angle\text{C}=\angle\text{F}$
For congruence, $BC = EF$
Therefore by $AAS$ axiom
$\triangle\text{ABC}≅\triangle\text{DEF}$

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