MCQ
In $\triangle\text{ABC},$ if $\angle\text{A}=100^\circ,\text{AD}$ bisects $\angle\text{A}$ and $\text{AD}\perp\text{BC}.$ Then, $\angle\text{B}=$
- A$50^\circ$
- B$90^\circ$
- ✓$40^\circ$
- D$100^\circ$

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