Question
In $\triangle\text{ABC},$ if $\angle\text{B}=76^\circ$ and $\angle\text{C}=48^\circ,$ find $\angle\text{A}.$
✓
Answer
Since, sum of the angles of a triangle is $180^\circ$
$\angle\text{A}+\angle\text{B}+\angle\text{C}=180^\circ$
$\Rightarrow\angle\text{A}+76^\circ+48^\circ=180^\circ$
$\Rightarrow\angle\text{A}=180^\circ-124^\circ=56^\circ$
$\therefore\angle\text{A}=56^\circ$
$\angle\text{A}+\angle\text{B}+\angle\text{C}=180^\circ$
$\Rightarrow\angle\text{A}+76^\circ+48^\circ=180^\circ$
$\Rightarrow\angle\text{A}=180^\circ-124^\circ=56^\circ$
$\therefore\angle\text{A}=56^\circ$
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