MCQ
In $\triangle\text{ABC},$ it is given that base $= 12\ cm$ and height $= 5\ cm.$ Its area is:
- A$60\ cm^2$
- B$15\sqrt3\text{cm}^2$
- C$45\ cm^2$
- ✓$30\ cm^2$
✓
Answer
Correct option: D.
$30\ cm^2$
$30\ cm^2$
Area of triangle $=\frac{1}{2}\times\text{Base}\times\text{Height}$
Are of $\triangle\text{ABC}=\frac{1}{2}\times12\times5$
$= 30\ cm^2$
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