MCQ
In $\triangle\text{PQR},$ if $\angle\text{P}=60^{\circ},$ and $\angle\text{Q}=40^{\circ},$ then the exterior angle formed by producing $QR$ is equal to:
- A$60^\circ$
- B$120^\circ$
- ✓$100^\circ$
- D$80^\circ$
✓
Answer
Correct option: C.
$100^\circ$
As we know, the measure of exterior angle is equal to the sum of opposite two interior angles.
In $\triangle\text{PQR},$ $\angle\text{x}$ is the exterior angle.
So, $\angle\text{x}=\angle\text{P}+\angle\text{Q}$
$=60^{\circ}+40^{\circ}=100^{\circ}$
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