MCQ
In weak alkaline medium iodide is changed in following compound by $KMnO_4$
- A$I_2$
- B$KI$
- C$IO^{-}_{2}$
- ✓$IO^{-}_{3}$
$I +6 OH ^{-} \rightarrow IO _3^{-}+3 H _2 O +6 e ^{-}$
When alkaline $KMnO 4$ is treated with $KI ^{-}{ }^{}$is oxidised to $IO _3{ }^{-}$.
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$Pt$ $\mid H _{2}$ $(g,1 \,bar)$ $\left| H ^{+}( aq ) \| Cu ^{2+}( aq )\right| Cu ( s )$
is $0.31\, V$. The $pH$ of the acidic solution is found to be $3 ,$ whereas the concentration of $Cu ^{2+}$ is $10^{- x } \,M$. The value of $x$ is $.....$
(Given: $E _{ Cu ^{2+} / Cu }^{\ominus}=0.34 \,V$ and $\frac{2.303 RT }{ F }=0.06\, V$ )
${C_6}{H_5} - N{H_2}\xrightarrow[{HCl}]{{NaN{O_2}}}A\xrightarrow{{CuCN}}B\xrightarrow{{{H_2}/Ni}}C\xrightarrow{{HN{O_2}}}D$
product $(D)$ would be
$Cu ( s )+ Sn ^{2+}( aq ) \rightarrow Cu ^{2+}( aq )+ Sn ( s )$
$\left( E _{ Sn ^{2+} \mid Sn }^{0}=-0.16\, V , E _{ Cu ^{2+} \mid Cu }^{0}=0.34\, V \right.$ Take $F=96500\, C\, mol ^{-1}$ )