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Benzene $(C_6H_6)$ $+\,C{{H}_{3}}-CH=C{{H}_{2}}\,\xrightarrow{{{H}^{\oplus }}}A\xrightarrow{{{O}_{2}}}B$ $\xrightarrow{{{H}^{\oplus }}\,/\,\Delta }C+$$\begin{matrix}
O \\
|| \\
C{{H}_{3}}-C-C{{H}_{3}} \\
\end{matrix}$
The structure of intermediate compound $'B'$ will be
$(A)$ and $(B)$ are
$(A)$ $E, F$ and $\mathrm{G}$ are resonance structures
$(B)$ $E, F$ and $E, G$ are tautomers
$(C)$ $\mathrm{F}$ and $\mathrm{G}$ are geometrical isomers
$(D)$ $\mathrm{F}$ and $\mathrm{G}$ are diasteromers
$\underset{(1)}{\mathop{C{{H}_{3}}C{{H}_{2}}CHO}}\,$
$\underset{(2)}{\mathop{\begin{matrix}
O \\
|| \\
C{{H}_{3}}-C-C{{H}_{3}} \\
\end{matrix}}}\,$
$\underset{(3)}{\mathop{C{{H}_{3}}-CH=CH-OH}}\,$
$(I)\, CO^{2-}_3$ $(II)\, XeF_4$ $(III)\, I^-_3$ $(IV)\, NCl_3$ $(V)$ $BeCl_2$