Download App

6.2. Equilibrium - II (icon Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.2. Equilibrium - II (icon Equilibrium)1 Mark
MCQ
In which case change in $pH$ is maximum? 
  • A
    $1\ ml$ solution of $pH = 2$ is diluted to $100\ ml$ 
  • B
    $0 .1\ mol$ of $NaOH$ is added into $100\ ml$ of $0.01\ M\ NaOH$ solution
  • C
    $100\ mL$ of $H_2O$ is added into $900\ mL$ of $0.01\ M\ NaOH$ solution
  • ✓
    $100\ mL$ of $pH = 2$ solution is mixed with $100\ mL$ of $pH = 12$
✓

Answer

Correct option: D.
$100\ mL$ of $pH = 2$ solution is mixed with $100\ mL$ of $pH = 12$
d

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 6.2. Equilibrium - II (icon Equilibrium)→6.2. Equilibrium - II (icon Equilibrium) — all question types→Chemistry STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

The bond length between $s{p^3}$ hybridised carbon atom and other carbon atom is minimum in
→
$PbCl_2$ has max. concentration of $1.0\times10^{-3}\, M$ in its saturated aq. solution at $25\,^oC$. Its solubility in $0.1\, M\, NaCl$ solution will be
→
If $0.1\, M, 100\, mL \,NaOH$ solution is mixed with $0.05\, M, 100\, mL \,H_2SO_4$ solution the $pH$ of resulting solution is :
→
$s{p^3}{d^2}$ hybrid orbitals are
→
Which gas formation takes places by the oxidation of carbon with conc. $H_2SO_4$ ?
→
The $pH $ value of $1.0 \times {10^{ - 8}}\,M\,HCl$ solution is less than $8$ because
→
Which of the following statements about photochemical smog is wrong?
→
Which of the following is correct $IUPAC$ name
→
The $IUPAC$ name of  $\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\ 
  {C{H_3} - C = CH - C{H_2} - C} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,COO{C_2}{H_5}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,OH\,} 
\end{array}$ is
→
Major product of this reaction will be :
→