MCQ
In which compound, the oxidation state of phosphorus is $+4$
- A${P_4}{O_{11}}$
- ✓${P_4}{O_8}$
- C$PC{l_5}$
- D$NC{l_5}$
$4 x+(-2 \times 8)=0$
$4 x-16=0$
$x=\frac{16}{4}=+4$
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[Note : Ignore the pairing energy]
(image) $\frac{{{H_2}}}{{pd - BaS{O_4}}}\,'A'$
The product $'A'$ is